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Old 09-22-2011, 11:38 AM
hanleyclifford hanleyclifford is offline
 
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Quote:
Originally Posted by Mark Millbauer View Post
From a WEB article on ignition systems:
"The coil is designed to operate on 9 volts. Battery voltage (12 volts) is reduced to 9 volts by the Ballast Resistor. When the ignition switch is in the run position, the coil is powered through the Ballast Resistor feeding it 9 volts; but when the ignition switch is turned to "start", the Ballast Resistor gets by-passed. This feeds full battery voltage to the coil for better starting. The starter motor is drawing battery voltage down to about 10 volts at this time."

We must either run a ballast resistor of the correct resistance for the volts our system is feeding it or, as Moyer states, a coil with internal resistance. It too must have the correct resistance for the voltage our system is trying to shove through it.

The type, operation and condition of the ignition switch is a key component here as well. As is the output of the charging system.


mark
Thank you, Mark; your post represents the conventional wisdom and still merits our attention.
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